I give up, i got 2415 legs.... but one way or another, thats a lot of pu$$y!

 

thats what i got too.

 

I don't have the program to try it but I came up with 1386 legs.....
Is that even close?
& WTF is up with 7 girls having 7 backpacks with a bunch of cats in em?

 

Okay all you "Math Wiz" kids. Let's see what you can do with this one! Add your name to the spreadsheet if you get it. This helps keep your mind sharp!

- There are 7 girls on a bus
- Each girl has 7 backpacks
- In each backpack, there are 7 big cats
- For every big cat there are 7 little cats

How many legs are there in the bus?

The number of legs is the password to unlock the Excel sheet.

If you open it, add your name, save it, forward it back to the person who sent it to you and on to anyone else you think might have fun with it.

Remember each cat has 4 legs, and each girl has 2, but the backpacks have none.

 

that was too easy Gregrob....lol

 

You guys are way off

 

Ya I figured it out first time!

 

Same here.

 

x2... wooooo

 

:doh::doh::doh::doh::doh::doh::doh::doh:

 

Okay WTF is it for the rest of us that didn't figgure it out?

 

A whole bunch of legs. Them must be some pretty tough girls.

 

There's less than 1 million legs...oke:

 

But more than 7 :hehe:

 

now i got it..... what a retard i am.

 

Exactly........

 

The answer has 5 digits if that helps anyone

 

I kept skipping parts of it by accident.:doh: Ended up posting it on CompD.

 

Got it, I like a good math problem.

 

Oh you do? Here's one for you I just made up..

If you accelerate from a stop and travel a total distance of 1,320 feet and have an accelertion rate of .409 and your speed when you cross the finish line is 166 FPS (Feet per second), how long did it take in seconds to travel the entire distance?

 

Oh you do? Here's one for you I just made up..

If you accelerate from a stop and travel a total distance of 1,320 feet and have an drag factor of .54 and your speed when you cross the finish line is 166 FPS (Feet per second), how long did it take in seconds to travel the entire distance?

Thats an impossible question. You have to factor in R/T as well as how long you spun the tires off the line. When I first when to the track, my first run had a 60' of 3 sec and my second run had a 60' of 2.2 sec. and my trap speeds were no more than .1 mph difference.

 

editted because i can't read...

are you accelerating in a linear pattern ??

 

If it helps, you can convert FPS into MPH by dividing FPS/1.477

 

just throw out reaction time, say its 0

 

o tay

 

Uhhh, RT has NOTHING to do with how quickly or how fast you run the 1/4 oke:

RT only tells you how fast you trip the lights.

You could set there for 10 minutes, then go and the ET and MPH would be the same as if you had cut a perfect light. oke:

 

Uhhh, RT has NOTHING to do with how quickly or how fast you run the 1/4 oke:

RT only tells you how fast you trip the lights.

You could set there for 10 minutes, then go and the ET and MPH would be the same as if you had cut a perfect light. oke:

Exactly! Thats why I said "0"!

 

To anyone who hasn't gotten it yet, I'll give you a hint.

The answer is btw 9,000 and 12,000

Needless to say, A LOT.

Read the question very slowly, think about what it's saying and make sure you multiply ALL cats x 4, and all ladies x 2 to get number of legs.

 

Got it....

in 3 minutes

 

So did you figure out the original problem oke: